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import matplotlib.pyplot as plt
equations = [ r"$\lim_{{x \to 0}} \left( \frac{1}{x} \right)$", r"Al aproximarse x a 0, \frac{1}{x} tiende a +\infty o -\infty", r"\rightarrow \infty", "", r"$\lim_{{x \to 5}} \left( \frac{x^2 - 25}{x + 5} \right)$", r"Factorizamos el numerador: x^2 - 25 = (x - 5)(x + 5)", r"\rightarrow \lim_{{x \to 5}} \left( \frac{(x - 5)(x + 5)}{x + 5} \right) = \lim_{{x \to 5}} (x - 5)", r"\rightarrow 0", "", r"$\lim_{{x \to 1}} \left( \frac{\sqrt{x} - 1}{x - 2} \right)$", r"Sustituimos directamente x = 1:", r"\rightarrow \frac{\sqrt{1} - 1}{1 - 2} = \frac{0}{-1}", r"\rightarrow 0", "", r"$\lim_{{x \to 1}} \left( \frac{x^3 + 1}{x - 1} \right)$", r"Factorizamos el numerador: x^3 + 1 = (x + 1)(x^2 - x + 1)", r"\rightarrow \lim_{{x \to 1}} \left( \frac{(x + 1)(x^2 - x + 1)}{x - 1} \right)", r"Sustituyendo directamente x = 1:", r"\rightarrow \frac{(1 + 1)(1^2 - 1 + 1)}{1 - 1} = \frac{2}{0}", r"\rightarrow \infty", "", r"$\lim_{{x \to 2}} \left( \frac{x^3 + 3x^2 - 10x}{2x - 5} \right)$", r"Factorizamos el numerador: x^3 + 3x^2 - 10x = x(x + 5)(x - 2)", r"\rightarrow \lim_{{x \to 2}} \left( \frac{x(x + 5)(x - 2)}{2x - 5} \right)", r"Sustituyendo directamente x = 2:", r"\rightarrow \frac{2(2 + 5)(2 - 2)}{4 - 5} = \frac{0}{-1}", r"\rightarrow 0", "", r"$\lim_{{x \to 0}} \left( \frac{10x}{2x + 5} \right)$", r"Simplificamos y sustituimos directamente:", r"\rightarrow \frac{10 \cdot 0}{2 \cdot 0 + 5} = \frac{0}{5}", r"\rightarrow 0", "", r"$\lim_{{x \to 1}} \left( \frac{\sqrt{x} - 1}{x - 1} \right)$", r"Usamos la regla de L'Hôpital:", r"\rightarrow \lim_{{x \to 1}} \left( \frac{\frac{d}{dx} (\sqrt{x} - 1)}{\frac{d}{dx} (x - 1)} \right)", r"\rightarrow \lim_{{x \to 1}} \left( \frac{\frac{1}{2\sqrt{x}}}{1} \right)", r"\rightarrow \frac{1}{2}" ]
fig, ax = plt.subplots(figsize=(10, 12))
ax.axis('off')
for i, eq in enumerate(equations): ax.text(0.1, 1 - i*0.05, eq, fontsize=14, va='top', ha='left')
plt.tight_layout() plt.show()
The text was updated successfully, but these errors were encountered:
Hola @AndyGS-lang, gracias por reportar tu problema. Podrías por favor explicarnos cuál es exactamente el problema que tienes?
Sorry, something went wrong.
ccordoba12
No branches or pull requests
import matplotlib.pyplot as plt
Datos de las ecuaciones en la sección 4 con procedimientos
equations = [
r"$\lim_{{x \to 0}} \left( \frac{1}{x} \right)$",
r"Al aproximarse x a 0, \frac{1}{x} tiende a +\infty o -\infty",
r"\rightarrow \infty",
"",
r"$\lim_{{x \to 5}} \left( \frac{x^2 - 25}{x + 5} \right)$",
r"Factorizamos el numerador: x^2 - 25 = (x - 5)(x + 5)",
r"\rightarrow \lim_{{x \to 5}} \left( \frac{(x - 5)(x + 5)}{x + 5} \right) = \lim_{{x \to 5}} (x - 5)",
r"\rightarrow 0",
"",
r"$\lim_{{x \to 1}} \left( \frac{\sqrt{x} - 1}{x - 2} \right)$",
r"Sustituimos directamente x = 1:",
r"\rightarrow \frac{\sqrt{1} - 1}{1 - 2} = \frac{0}{-1}",
r"\rightarrow 0",
"",
r"$\lim_{{x \to 1}} \left( \frac{x^3 + 1}{x - 1} \right)$",
r"Factorizamos el numerador: x^3 + 1 = (x + 1)(x^2 - x + 1)",
r"\rightarrow \lim_{{x \to 1}} \left( \frac{(x + 1)(x^2 - x + 1)}{x - 1} \right)",
r"Sustituyendo directamente x = 1:",
r"\rightarrow \frac{(1 + 1)(1^2 - 1 + 1)}{1 - 1} = \frac{2}{0}",
r"\rightarrow \infty",
"",
r"$\lim_{{x \to 2}} \left( \frac{x^3 + 3x^2 - 10x}{2x - 5} \right)$",
r"Factorizamos el numerador: x^3 + 3x^2 - 10x = x(x + 5)(x - 2)",
r"\rightarrow \lim_{{x \to 2}} \left( \frac{x(x + 5)(x - 2)}{2x - 5} \right)",
r"Sustituyendo directamente x = 2:",
r"\rightarrow \frac{2(2 + 5)(2 - 2)}{4 - 5} = \frac{0}{-1}",
r"\rightarrow 0",
"",
r"$\lim_{{x \to 0}} \left( \frac{10x}{2x + 5} \right)$",
r"Simplificamos y sustituimos directamente:",
r"\rightarrow \frac{10 \cdot 0}{2 \cdot 0 + 5} = \frac{0}{5}",
r"\rightarrow 0",
"",
r"$\lim_{{x \to 1}} \left( \frac{\sqrt{x} - 1}{x - 1} \right)$",
r"Usamos la regla de L'Hôpital:",
r"\rightarrow \lim_{{x \to 1}} \left( \frac{\frac{d}{dx} (\sqrt{x} - 1)}{\frac{d}{dx} (x - 1)} \right)",
r"\rightarrow \lim_{{x \to 1}} \left( \frac{\frac{1}{2\sqrt{x}}}{1} \right)",
r"\rightarrow \frac{1}{2}"
]
Crear una figura
fig, ax = plt.subplots(figsize=(10, 12))
Ocultar ejes
ax.axis('off')
Añadir las ecuaciones
for i, eq in enumerate(equations):
ax.text(0.1, 1 - i*0.05, eq, fontsize=14, va='top', ha='left')
Ajustar el diseño y mostrar la imagen
plt.tight_layout()
plt.show()
The text was updated successfully, but these errors were encountered: